Integrand size = 22, antiderivative size = 108 \[ \int \tan (c+d x) (a+i a \tan (c+d x))^4 \, dx=-8 i a^4 x-\frac {8 a^4 \log (\cos (c+d x))}{d}+\frac {4 i a^4 \tan (c+d x)}{d}+\frac {a (a+i a \tan (c+d x))^3}{3 d}+\frac {(a+i a \tan (c+d x))^4}{4 d}+\frac {\left (a^2+i a^2 \tan (c+d x)\right )^2}{d} \]
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Time = 0.09 (sec) , antiderivative size = 108, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.182, Rules used = {3608, 3559, 3558, 3556} \[ \int \tan (c+d x) (a+i a \tan (c+d x))^4 \, dx=\frac {4 i a^4 \tan (c+d x)}{d}-\frac {8 a^4 \log (\cos (c+d x))}{d}-8 i a^4 x+\frac {\left (a^2+i a^2 \tan (c+d x)\right )^2}{d}+\frac {a (a+i a \tan (c+d x))^3}{3 d}+\frac {(a+i a \tan (c+d x))^4}{4 d} \]
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Rule 3556
Rule 3558
Rule 3559
Rule 3608
Rubi steps \begin{align*} \text {integral}& = \frac {(a+i a \tan (c+d x))^4}{4 d}-i \int (a+i a \tan (c+d x))^4 \, dx \\ & = \frac {a (a+i a \tan (c+d x))^3}{3 d}+\frac {(a+i a \tan (c+d x))^4}{4 d}-(2 i a) \int (a+i a \tan (c+d x))^3 \, dx \\ & = \frac {a (a+i a \tan (c+d x))^3}{3 d}+\frac {(a+i a \tan (c+d x))^4}{4 d}+\frac {\left (a^2+i a^2 \tan (c+d x)\right )^2}{d}-\left (4 i a^2\right ) \int (a+i a \tan (c+d x))^2 \, dx \\ & = -8 i a^4 x+\frac {4 i a^4 \tan (c+d x)}{d}+\frac {a (a+i a \tan (c+d x))^3}{3 d}+\frac {(a+i a \tan (c+d x))^4}{4 d}+\frac {\left (a^2+i a^2 \tan (c+d x)\right )^2}{d}+\left (8 a^4\right ) \int \tan (c+d x) \, dx \\ & = -8 i a^4 x-\frac {8 a^4 \log (\cos (c+d x))}{d}+\frac {4 i a^4 \tan (c+d x)}{d}+\frac {a (a+i a \tan (c+d x))^3}{3 d}+\frac {(a+i a \tan (c+d x))^4}{4 d}+\frac {\left (a^2+i a^2 \tan (c+d x)\right )^2}{d} \\ \end{align*}
Time = 0.27 (sec) , antiderivative size = 67, normalized size of antiderivative = 0.62 \[ \int \tan (c+d x) (a+i a \tan (c+d x))^4 \, dx=\frac {a^4 \left (19+96 \log (i+\tan (c+d x))+96 i \tan (c+d x)-42 \tan ^2(c+d x)-16 i \tan ^3(c+d x)+3 \tan ^4(c+d x)\right )}{12 d} \]
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Time = 0.28 (sec) , antiderivative size = 72, normalized size of antiderivative = 0.67
method | result | size |
derivativedivides | \(\frac {a^{4} \left (8 i \tan \left (d x +c \right )+\frac {\left (\tan ^{4}\left (d x +c \right )\right )}{4}-\frac {4 i \left (\tan ^{3}\left (d x +c \right )\right )}{3}-\frac {7 \left (\tan ^{2}\left (d x +c \right )\right )}{2}+4 \ln \left (1+\tan ^{2}\left (d x +c \right )\right )-8 i \arctan \left (\tan \left (d x +c \right )\right )\right )}{d}\) | \(72\) |
default | \(\frac {a^{4} \left (8 i \tan \left (d x +c \right )+\frac {\left (\tan ^{4}\left (d x +c \right )\right )}{4}-\frac {4 i \left (\tan ^{3}\left (d x +c \right )\right )}{3}-\frac {7 \left (\tan ^{2}\left (d x +c \right )\right )}{2}+4 \ln \left (1+\tan ^{2}\left (d x +c \right )\right )-8 i \arctan \left (\tan \left (d x +c \right )\right )\right )}{d}\) | \(72\) |
parallelrisch | \(-\frac {16 i a^{4} \left (\tan ^{3}\left (d x +c \right )\right )-3 \left (\tan ^{4}\left (d x +c \right )\right ) a^{4}+96 i a^{4} x d -96 i a^{4} \tan \left (d x +c \right )+42 a^{4} \left (\tan ^{2}\left (d x +c \right )\right )-48 a^{4} \ln \left (1+\tan ^{2}\left (d x +c \right )\right )}{12 d}\) | \(83\) |
risch | \(\frac {16 i a^{4} c}{d}-\frac {4 a^{4} \left (30 \,{\mathrm e}^{6 i \left (d x +c \right )}+63 \,{\mathrm e}^{4 i \left (d x +c \right )}+50 \,{\mathrm e}^{2 i \left (d x +c \right )}+14\right )}{3 d \left ({\mathrm e}^{2 i \left (d x +c \right )}+1\right )^{4}}-\frac {8 a^{4} \ln \left ({\mathrm e}^{2 i \left (d x +c \right )}+1\right )}{d}\) | \(88\) |
norman | \(-\frac {7 a^{4} \left (\tan ^{2}\left (d x +c \right )\right )}{2 d}+\frac {a^{4} \left (\tan ^{4}\left (d x +c \right )\right )}{4 d}-8 i a^{4} x +\frac {8 i a^{4} \tan \left (d x +c \right )}{d}-\frac {4 i a^{4} \left (\tan ^{3}\left (d x +c \right )\right )}{3 d}+\frac {4 a^{4} \ln \left (1+\tan ^{2}\left (d x +c \right )\right )}{d}\) | \(92\) |
parts | \(\frac {7 a^{4} \ln \left (1+\tan ^{2}\left (d x +c \right )\right )}{2 d}+\frac {a^{4} \left (\frac {\left (\tan ^{4}\left (d x +c \right )\right )}{4}-\frac {\left (\tan ^{2}\left (d x +c \right )\right )}{2}+\frac {\ln \left (1+\tan ^{2}\left (d x +c \right )\right )}{2}\right )}{d}-\frac {4 i a^{4} \left (\frac {\left (\tan ^{3}\left (d x +c \right )\right )}{3}-\tan \left (d x +c \right )+\arctan \left (\tan \left (d x +c \right )\right )\right )}{d}+\frac {4 i a^{4} \left (\tan \left (d x +c \right )-\arctan \left (\tan \left (d x +c \right )\right )\right )}{d}-\frac {3 a^{4} \left (\tan ^{2}\left (d x +c \right )\right )}{d}\) | \(138\) |
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Time = 0.23 (sec) , antiderivative size = 174, normalized size of antiderivative = 1.61 \[ \int \tan (c+d x) (a+i a \tan (c+d x))^4 \, dx=-\frac {4 \, {\left (30 \, a^{4} e^{\left (6 i \, d x + 6 i \, c\right )} + 63 \, a^{4} e^{\left (4 i \, d x + 4 i \, c\right )} + 50 \, a^{4} e^{\left (2 i \, d x + 2 i \, c\right )} + 14 \, a^{4} + 6 \, {\left (a^{4} e^{\left (8 i \, d x + 8 i \, c\right )} + 4 \, a^{4} e^{\left (6 i \, d x + 6 i \, c\right )} + 6 \, a^{4} e^{\left (4 i \, d x + 4 i \, c\right )} + 4 \, a^{4} e^{\left (2 i \, d x + 2 i \, c\right )} + a^{4}\right )} \log \left (e^{\left (2 i \, d x + 2 i \, c\right )} + 1\right )\right )}}{3 \, {\left (d e^{\left (8 i \, d x + 8 i \, c\right )} + 4 \, d e^{\left (6 i \, d x + 6 i \, c\right )} + 6 \, d e^{\left (4 i \, d x + 4 i \, c\right )} + 4 \, d e^{\left (2 i \, d x + 2 i \, c\right )} + d\right )}} \]
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Time = 0.28 (sec) , antiderivative size = 170, normalized size of antiderivative = 1.57 \[ \int \tan (c+d x) (a+i a \tan (c+d x))^4 \, dx=- \frac {8 a^{4} \log {\left (e^{2 i d x} + e^{- 2 i c} \right )}}{d} + \frac {- 120 a^{4} e^{6 i c} e^{6 i d x} - 252 a^{4} e^{4 i c} e^{4 i d x} - 200 a^{4} e^{2 i c} e^{2 i d x} - 56 a^{4}}{3 d e^{8 i c} e^{8 i d x} + 12 d e^{6 i c} e^{6 i d x} + 18 d e^{4 i c} e^{4 i d x} + 12 d e^{2 i c} e^{2 i d x} + 3 d} \]
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Time = 0.30 (sec) , antiderivative size = 82, normalized size of antiderivative = 0.76 \[ \int \tan (c+d x) (a+i a \tan (c+d x))^4 \, dx=\frac {3 \, a^{4} \tan \left (d x + c\right )^{4} - 16 i \, a^{4} \tan \left (d x + c\right )^{3} - 42 \, a^{4} \tan \left (d x + c\right )^{2} - 96 i \, {\left (d x + c\right )} a^{4} + 48 \, a^{4} \log \left (\tan \left (d x + c\right )^{2} + 1\right ) + 96 i \, a^{4} \tan \left (d x + c\right )}{12 \, d} \]
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Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 222 vs. \(2 (94) = 188\).
Time = 0.55 (sec) , antiderivative size = 222, normalized size of antiderivative = 2.06 \[ \int \tan (c+d x) (a+i a \tan (c+d x))^4 \, dx=-\frac {4 \, {\left (6 \, a^{4} e^{\left (8 i \, d x + 8 i \, c\right )} \log \left (e^{\left (2 i \, d x + 2 i \, c\right )} + 1\right ) + 24 \, a^{4} e^{\left (6 i \, d x + 6 i \, c\right )} \log \left (e^{\left (2 i \, d x + 2 i \, c\right )} + 1\right ) + 36 \, a^{4} e^{\left (4 i \, d x + 4 i \, c\right )} \log \left (e^{\left (2 i \, d x + 2 i \, c\right )} + 1\right ) + 24 \, a^{4} e^{\left (2 i \, d x + 2 i \, c\right )} \log \left (e^{\left (2 i \, d x + 2 i \, c\right )} + 1\right ) + 30 \, a^{4} e^{\left (6 i \, d x + 6 i \, c\right )} + 63 \, a^{4} e^{\left (4 i \, d x + 4 i \, c\right )} + 50 \, a^{4} e^{\left (2 i \, d x + 2 i \, c\right )} + 6 \, a^{4} \log \left (e^{\left (2 i \, d x + 2 i \, c\right )} + 1\right ) + 14 \, a^{4}\right )}}{3 \, {\left (d e^{\left (8 i \, d x + 8 i \, c\right )} + 4 \, d e^{\left (6 i \, d x + 6 i \, c\right )} + 6 \, d e^{\left (4 i \, d x + 4 i \, c\right )} + 4 \, d e^{\left (2 i \, d x + 2 i \, c\right )} + d\right )}} \]
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Time = 4.81 (sec) , antiderivative size = 72, normalized size of antiderivative = 0.67 \[ \int \tan (c+d x) (a+i a \tan (c+d x))^4 \, dx=\frac {8\,a^4\,\ln \left (\mathrm {tan}\left (c+d\,x\right )+1{}\mathrm {i}\right )-\frac {7\,a^4\,{\mathrm {tan}\left (c+d\,x\right )}^2}{2}+\frac {a^4\,{\mathrm {tan}\left (c+d\,x\right )}^4}{4}+a^4\,\mathrm {tan}\left (c+d\,x\right )\,8{}\mathrm {i}-\frac {a^4\,{\mathrm {tan}\left (c+d\,x\right )}^3\,4{}\mathrm {i}}{3}}{d} \]
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